select NAME, rank, count, surname_entries.id 'wiki_id' from surnames left join surname_entries on surname_entries.surname = surnames.name and surname_entries.entry_type = 1 where index2 = 'CO' order by rank asc limit 0,100 Surnames > C > CO > %22

Surnames > C > CO > %22

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
CA CD CE CH CI CL CM CN CO CR CS CU CV CW CY CZ
CO COA COB COC COD COE COF COG COH COI COJ COK COL COM CON COO COP COQ COR COS COT COU COV COW COX COY COZ

Full Surname List Starting with %22(Alphabetical)